1. The EPA claims that fluoride in children’s drinking water should be at a mean level of less than 1.2 ppm, or parts per million, to reduce the number of dental cavities. Identify the Type I error. (Points : 1) |
[removed] Fail to support the claim σ < 1.2 when σ < 1.2 is true.
[removed] Support the claim μ < 1.2 when μ = 1.2 is true.
[removed] Support the claim σ < 1.2 when σ = 1.2 is true.
[removed] Fail to support the claim μ < 1.2 when μ < 1.2 is true.
2.
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3.Researchers studying sleep loss followed the length of sleep, in hours, of 10 individuals with insomnia before and after cognitive behavioral therapy (CBT). Assume a .05 significance level to test the claim that there is a difference between the length of sleep of individuals before and after CBT. Also, assume the data consist of matched pairs, the samples are simple random samples, and the pairs of values are from a population having a distribution that is approximately normal.
Individual |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
Before |
6 |
5 |
4 |
5 |
3 |
4 |
5 |
3 |
4 |
2 |
CBT |
|
|
|
|
|
|
|
|
|
|
After |
8 |
8 |
7 |
6 |
7 |
6 |
6 |
5 |
7 |
5 |
CBT |
|
|
|
|
|
|
|
|
|
|
Construct a 95% confidence interval estimate of the mean difference between the lengths of sleep. Give your answer with two decimals, e.g., (12.34,56.78) (Points : 0.5)
[removed]
4.
The paired data consist of the cost of regionally advertising (in thousands of dollars) a certain pharmaceutical drug and the number of new prescriptions written (in thousands).
[removed] |
5.
Use a .05 significance level and the observed frequencies of 144 drownings at the beaches of a randomly selected coastal state to test the claim that the number of drownings for each month is equally likely.
[removed] |
6.
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7.
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8.
Geneticists studying carriers of genetic diseases followed subjects subdivided by race. Researchers randomly selected seven patients per race who had been identified as carrying a certain gene for a genetic disease; these patients were followed to determine the number of their siblings who also carried the gene for the genetic disease. Use a One-Way ANOVA at a .05 significance level to test the claim that the means from the different races are not all the same.
[removed] |
9.
Question 9 of 10If there is only one observation per cell in a Two-Way ANOVA, and it can be assumed there is not an interaction between factors, then we can proceed to interpret the results of the row and column effects. (Points : 1) |
[removed] True
[removed] False
10.
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4 years ago
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