Laboratory – 4Title – Determination of Phosphate concentration
Purpose- Study of samples of phosphorous ions (HPO42- or H2PO4-) using
Nuclear Magnetic Resonance.
1. After the instructor’s demonstration, we placed 0.5mL of the sample in the tube and then
added 0.1mL of D2O in the same tube.
We collected data from the software as par the given instruction. To collect data we used
following steps –
a. We Opened a data file from the folder labelled CHM 152. Then clicked the start
button. In this menu created new data set. We advanced the exp # by one. Then
b. Now, we opened the Acquire menu. Went to sample, pulled down to turn on
airlift to remove the sample currently in the NMR. Carefully removed the sample
from the NMR and replaced it with our sample.
c. Lowered the sample into the NMR waited for it to click. Then clicked Lock, the
lock found the signal of solvent to calibrate the RF frequency.
d. Next clicked Tune. This set the RF frequency for the sample.
e. Then turned on the spin
f. Next, clicked on the Shim. It made fine adjustments to the magnetic field.
g. Again, clicked prosol, then Gain then Go.
Waited for the spectrum to be collected for around 10 minutes.
After the step 3 completed, Clicked Process. This converted the FID to a conventional
To integrate the peak first clicked on find peaks automatically, then integrated
Observations – add more
There were five samples with different concentration. They were 50ppm, 100ppm,
150ppm, 200ppm and 250ppm.
Data and Calculations – in the lab we had different drink no peak) for Pellegrino
( you may explain this in conclusion, why there is no peak I think the high peak
was for coke
878,437 __ coke
Results and Conclusions –
The maximum value of intensity obtained was 33.8616 and corresponding to this peak intensity,
we have 47.753ppm concentration of phosphate ions. We observed only one peak in this
experiment so that there is only one type of nuclei which absorb energy. The integrated peak area
is proportional to the number of nuclei, which absorb at that frequency. Since phosphorus has 15
electrons total. It has one electron unpaired. It is a diamagnetic element. In all the samples in this
experiment phosphorus appears as either HPO2-4or H2PO4-. These two ions rapidly convert from
one form to the other during the time frame of the experiment. This means that only one peak is
observed in the final spectrum. The area of the peak is proportional to the total phosphate
1. Our NMR machine is designed to have the 1H signal resonate at 400MHz. What is
the size of the magnetic field in Tesla?
Sol. – Since, ν = γB, Where γ is gyromagnetic ratio.
And γ = 42.58MHz/T
400 = 42.58*B
B = 9.3941 Tesla Ans.
2. What is the resonant frequency of the 31P atom in this magnetic field? What region
of the electromagnetic spectrum is it?
Since, ν = γB, and γ for 31P is 17.24MHz/Tesla and B = 2.35T
v = 2.35*17.24 = 40.514MHz
This lies in Radio Wave range.
Title – Estimation of phosphate in beverage.
Purpose – Estimation of phosphate content in beverage with the help of optical spectroscopy.
Procedure: 1. From the stock solution of 20 ppm phosphate solution make five standard solutions of 0.5
ppm, 1 ppm, 1.5 ppm, 2 ppm and 2.5 ppm. The total volume of each solution should be
Volume of 20 ppm solution added mL
Concentration of the standard ppm
2. Prepare the Spec 20 to read the samples at 650 nm.
3. To each of the 25 mL standard samples add 1.00 mL of the ammonium molybdate
solution. Add 2 drops of the stannous chloride solution. And mix. Do the same for your
4. After 5 minutes measure the absorbance of the standards and the samples.
When phosphate reacted with ammonium molybdate, it turned out to be blue. The absorbance
value was increasing with the concentration. Absorbance is directly proportional to concentration
of the solution and optical path length.
Data and Calculations –
Un know 1 coke
Unknow 2 pellegrino
Results and Conclusions
From the graph, we see that Absorbance is directly proportional to concentration.
Actually, the Beer law is A = εlc where
𝜀 𝑖𝑠 𝑚𝑜𝑙𝑎𝑟 𝑎𝑏𝑠𝑜𝑟𝑝𝑡𝑖𝑜𝑛 𝑐𝑜𝑒𝑓𝑓𝑖𝑐𝑖𝑒𝑛𝑡 𝑎𝑛𝑑 “𝑙” 𝑖𝑠 𝑜𝑝𝑡𝑖𝑐𝑎𝑙 𝑝𝑎𝑡ℎ 𝑙𝑒𝑛𝑔𝑡ℎ. The concentration of
unknown sample is 0.9814mol/liter and it is less than that of 2.5. From this data, we can
calculate concentration for several unknown samples. ( edit this part or rewirte the
result and conclusions)
Discuss the differences and similarities of the 2 techniques –
In both cases we calculated concentration of unknown solution. Both the cases
included absorbance and wavelength.
First case was more difficult to complete but second one is simpler. For second
case, we needed a greater number of solution but in first only one solution is
required. The required one is unknown sample in first case. First one is based on
the principle of magnetic properties of element in the solution. In second case,
the absorbed radiant energy is directly proportional to that of dissolved substance
in the solution. In first case, energy absorbed is directly proportional to energy
gap between stable and unstable state.
Laboratory 4 Determination of Phosphate Using Two
Different Techniques, Optical Spectroscopy and Nuclear
Nuclear Magnetic Resonance:
Protons and Neutrons, like electrons, also have the quantum property of spin.
Depending on the total number of protons and neutrons in the nucleus, the
nucleus may have unpaired spins. In this case, when the atom with a nuclear
spin is placed in a magnetic field, the spin may either align with the magnetic field
or opposed to the magnetic field.
The spin, which is opposed to the
magnetic field, is at higher energy
than the spin which is aligned with
the magnetic field. The separation
between the two states is
proportional to the strength of the
Magnetic field B
The greater the magnetic field, the greater the separation between the two
states. The separation may be expressed as the frequency of radiation with that
energy, ν. If the strength of the magnetic field is B, the equation which relates
ν = γB
where γ is the gyromagnetic ratio of the particular nucleus. Different nuclei will
have a different resonant frequency in the same magnetic field.
In NMR spectroscopy, the sample is placed in a strong magnetic field. This
separates the nuclear spin states (aligned with the field or opposed to the field).
Radiating the sample with of the correct frequency will cause nuclei in the lower
energy state (aligned with the field) to move into the excited state (opposed to
the field). The sample will then relax over time to the lower energy state.
NMR spectroscopy is such a powerful tool for structural information because not
only do the different nuclei have different resonance frequencies, but also nuclei
in different chemical environments have measurably different frequencies. We
will study the phosphorous nucleus. In all the samples in this experiment
phosphorus appears as either HPO4-2 or H2PO4-. These two ions rapidly convert
from one form to the other during the time frame of the experiment. This means
that only one peak is observed in the final spectrum. The area of the peak is
proportional to the total phosphate concentration.
The Bruker NMR and software:
The NMR consists of a large magnet which holds the sample and the probe. The
probe is a radio frequency (RF) detector. There is also a computer to control the
console, and an electronic console, which controls the temperature of the
instrument, the RF pulses, the shim magnet system, and detects the RF signal.
The instrument is a Fourier Transform NMR, which means that the RF
frequencies are collected all at once. The original data from the instrument
comes in the form of a Free Induction Decay (FID).
An example of an FID is shown in figure 1.
Amplitude of Signal
Free Induction Decay
The signal naturally decays with time, the oscillations correspond to a resonant
frequency. The data is transformed from the frequency domain by a Fourier
Transform. After this process a more traditional spectrum is obtained.
The integrated peak area is proportional to the number of nuclei, which absorb at
For the NMR spectroscopy section, we will work as one big group.
The instructors have made a set of NMR standards with the following
concentration of phosphate: 50 ppm, 100 ppm, 150 ppm, 200 ppm, and 250
The standards have been placed into NMR tubes and labeled. The instructor will
demonstrate filling the tubes. You will place 0.5 mL of your sample in the tube
and then add 0.1 mL of D2O to the same tube. The tubes are fragile and
expensive. Be careful.
2. Collect the NMR data for your unknown. The software is designed to be read
and implemented from left to right.
a. Open a data file from the folder labelled CHM 152. Then click the start
button. In this menu create new data set. You will need to advance the exp #
by one. Then click OK.
b. Now open the Acquire menu. Go to sample, pull down to turn on airlift to
remove the sample currently in the NMR. Carefully remove the sample from the
NMR and replace it with your sample. The instructor will demonstrate.
c. Lower the sample into the NMR wait for it to click. Then click Lock, the lock
finds the signal of solvent to calibrate the RF frequency.
d. Next click Tune. This sets the RF frequency for the sample.
e. Then turn on the spin.
f. Next click on Shim. This makes fine adjustments to the magnetic field.
g. Next Click prosol, then gain then go.
Now wait for the spectrum to be collected.
It may look like this:
This is a Free Induction Decay.
When that is done, click Process. This converts the FID to a conventional
There should be one phosphate peak.
To integrate the peak first click on find peaks automatically, then integrate
automatically: Open the integration table. It may look like this:
The peak has a chemical shift close to 0.0, The value needed is the Integration
[ABS]. Record this number to share with your classmates.
Plot the standard curve and determine the amount of phosphate in the
1. Our NMR machine is designed to have the 1H signal resonate at 400MHz.
What is the size of the magnetic field in Telsa?
2. What is the resonant frequency of the 31P atom in this magnetic field? What
region of the electromagnetic spectrum is it?
Part 2: UV/VIS method to measure phosphate in
(Do this while waiting to take your NMR spectrum)
We will use in this experiment the unit ppm or part per million. One ppm =
1 part per million, or 1 milligram solute/kg solvent. In water this is 1 mg/liter.
Phosphate reacts with ammonium molybdate, (NH4)2MoO4 to form
molybophosphoric acid, 12MoO3 • H3PO4 . This is reduced by stannous chloride
to form molybdenum blue, which consists of mainly MoO2, and is a highly colored
compound which absorbs at 650 nm.
1. From the stock solution of 20 ppm phosphate solution make five standard
solutions of 0.5 ppm, 1 ppm, 1.5 ppm, 2 ppm and 2.5 ppm. The total volume of
each solution should be 25 mL. Determine the volume of the 20 ppm solution
needed to make each diluted solution.
Volume of 20 ppm
solution added mL
the standard ppm
2. Prepare the Spec 20 to read the samples at 650 nm.
3. Color develop the standards and the samples.
To each of the 25 mL standard samples add 1.00 mL of the ammonium molydate
solution. Add 2 drops of the stannous chloride solution. And mix. Do the same
for your unknown samples.
4. After 5 minutes measure the absorbance of the standards and the samples.
Make a Beer’s Law plot of the standard concentration versus absorbance and
use this to determine the concentration of the unknown samples. If the
concentration of your unknown sample is greater than 2.5 ppm you will need to
dilute it until it is less than 2.5 ppm. If you do not yet known the concentration
(but your absorbance reading exceeds the absorbance of the 2.5 ppm sample)
make a 1 to 10 dilution and a 1 to 100 dilution and then repeat the experiment for
your known from part 3. Determine the concentration of the unknowns.
Remember to include any dilutions.
Discuss the differences and similarities of the 2 techniques.
Safety and Disposal: Place the waste in the container provided.
Measurement of Physical Properties
In any measurement it is important to know the precision of the
measurement and also its accuracy. All physical measurements should be made
as precisely and accurately as possible. Maximizing the precision of a
measurement is accomplished by using the most precise equipment available,
and using it properly. If possible it is also wise to compare your result with either
a known or theoretical value.
When calculating a result from more than one measurement it important to
retain the uncertainty information from all the measurements. There is an entire
field of mathematics devoted to this topic. In this course we use the relatively
simple method of significant figures. A summary of the rules with examples:
Addition and subtraction: line up the numbers to be added or subtracted;
the answer is truncated to the decimal place of the least precise number.
Ex. 12.1 + 2.345 = 14.4
15.678 – 2.2 = 13.5 (notice I rounded up)
Multiplication and Division: Significant Figures in the answer are equal to
the number of significant figures in the least precise number.
15.6 x 2.1 = 31
16.789 ⎟ 25.67432 = 0.65392
25.1 x 3.00 = 75.0
Note zeroes before another number as in 0.65392 do not count. In the
middle and the end they count.
In this course you will be required to keep a laboratory notebook. A good
laboratory notebook is an accurate record of everything, which occurred in the
lab. In patent disputes a good lab book versus an inaccurate lab book can mean
millions of dollars. In this course it may mean hundreds of points. Before the lab
you will be required to prepare a lab report outline to be completed during the lab
session. Each lab report will contain:
Title and Purpose
1. Procedure and Observations
2. Data and Calculations
3. Results and Conclusions
4. Answers to questions in manual
An example of a lab report is shown below:
1. Title: Density of liquid and a solid.
Purpose to measure the density of a liquid and an unknown solid.
Part 1 Liquid
Unknown # 5 smells like gasoline
Weigh an empty 10.0 mL volumetric flask
Fill with unknown liquid.
Weigh filled volumetric flask
Mass of empty flask = 12.032 grams
Mass of full flask = 18.685 grams
Part 2 Solid
Part 2 Unknown #12 Shiny orange color
Fill a graduated cylinder with about 25 mL of
Measure precisely volume of water.
Volume of water = 24.83 mL
Volume of water + metal = 28.53 mL
Mass of Dry metal = 46.409 grams
weigh dry solid sample
Data and Calculations:
Part 1 Liquid:
Density = Mass / volume
Mass of liquid = mass of liquid + flask – mass of flask = 18.685 grams – 12.032 grams = 6.652
Density = 6.652 grams / 10.000 mL = 0.6652 g/mL
Part 2 solid
volume of solid = volume of solid + water – volume water = 28.53 mL – 24.83 mL = 3.70 mL
density = 46.409 g/3.70 mL = 12.5 g/mL
Results and Conclusions:
The density of the liquid was determined to be 0.6652 g/mL by comparison with the
density table in the CRC it appears the sample could be hexane, which has a density of 0.660
The density of solid was 12.5 grams / mL. The solid looked like copper, but the density of
copper from the CRC is: 8.94 g/mL, which is significantly less than my unknown sample.
Therefore although the sample looks like copper it must be something else.
In this example, the data is recorded in the section with the observations,
and the procedure is recorded in one column and the observations are recorded
in an adjoining column. This allows you to record your observations with the
correct section of the procedure. In some experiments, the type and volume of
data is better recorded in a table. In this case it should follow the procedure
section. You should still leave room in the procedure section for observations.
One of the objectives of this course is for students to learn how to determine
what data they need to collect, and how to organize it. For some experiments
explicit instructions for organizing the data and calculations will be given, but for
other experiments you will need to determine this for yourself before class. In the
case of repetitive calculations tables are necessary. A spreadsheet such as
Excel can be used, and instructions are included for the Reaction Rate
experiment. All your calculations must follow the rules for significant figures and
every value must have a correct unit. A spreadsheet or calculator will not
determine the correct number of significant figures; it is up to you.
When determining the results and conclusions, there are some things to
keep in mind. The results should relate back to the purpose. Address directly if
the purpose was fulfilled. If the result is a number clearly restate what it is and
the unit for the number. If possible compare your result with a literature value. If
you received no result or an unexpected result, give some scientific explanation
of this. Human error is not a good explanation, because the experiment or
section, which was in error, should be repeated. Thoroughness is important but it
is not necessary to write everything you know about density or volume etc.
To be ready to use all the lab time efficiently, before lab class you should
have completed the purpose, procedure and arranged the data table or written
down what you need to measure.
Lab Instructors may have additional report requirements.
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